The Joint CSIR NET is a test being held to examine the eligibility of Indian nationals for Junior Research Fellowship (JRF) and Lectureship (LS)/Assistant Professor in Indian institutions and colleges that meet the UGC eligibility requirements. The Council of Scientific and Industrial Research (CSIR) has tasked the National Testing Agency (NTA) with conducting the Joint CSIR-UGC NET December 2023 / June 2024 Examination under the Computer Based Test (CBT) format.
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The Council of Scientific and Industrial Research (CSIR) is a modern R&D organization noted for its cutting-edge R&D knowledge base in several S&T domains. CSIR and UGC provide Research Fellowships for training in research methodologies under the professional direction of faculty members/scientists working in university departments, national laboratories, and institutions in various scientific subjects.
Oceanography, geophysics, chemicals, medicines, genomics, biotechnology, and nanotechnology are all covered by CSIR, and mining, aeronautics, instrumentation, environmental engineering, and information technology. It offers considerable technology involvement in many social initiatives, including the environment, health, drinking water, food, housing, energy, and farm and non-farm sectors. Furthermore, CSIR’s contribution to S&T’s human resource development is notable.
Particulars | Elaboration |
Exam | Council of Scientific and Industrial Research National Eligibility Test (CSIR NET) |
Conducted By | Exam Level |
Examination purpose | To determine applicants’ eligibility for Junior Research Fellowship (JRF) and Lectureship (LS)/ Assistant Professor at Indian institutions and colleges. |
Exam Level | National level |
Exam Centres | 225 |
Examination frequency | Twice a year |
Mode of Exam | Online – Computer-Based Test (CBT) |
Medium of Exam | English and Hindi |
No. of papers | 2 |
Application Mode | Online |
Online – Computer-Based Test (CBT) | INR 1,100 for the General category INR 550 for OBC INR 275 for SC/ ST INR 0 for PwD |
Exam Duration | 3 Hours (180 Minutes) |
Exam Shift | Shift 1 – 09:00 am to 12:00 noon Shift 2 – 03:00 pm to 06:00 pm |
No. of Questions | 150 MCQ in each Paper |
Total Marks | Paper 1- 200 Paper 2- 200 |
Marking Schemes | +2 for each correct answer 0.25 mark deduction for each wrong answer |
Exam Help Desk Number | 0120-6895200 |
Official website | https://csirnet.nta.nic.in/ https://nta.ac.in/ |
The NTA has released the CSIR NET Application Form 2024.
csir-net-june-2024The exam schedule for all disciplines will be posted on the CSIR website soon.
Particulars | Dates |
CSIR NET Notification | 1st May 2024 |
CSIR NET Application Form | 1st May 2024 |
CSIR NET Application Form (Last date of Submission) | 21st May 2024 |
CSIR NET Application Form (Correction Window) | 25th to 27th May 2024 |
CSIR NET Admit Card | To Be Notified |
CSIR NET Exam Date | 25th, 26th, 27th June 2024 |
CSIR NET Provisional Answer Key Release | To Be Notified |
CSIR NET Objection Window Provisional Answer Key | To Be Notified |
CSIR NET Final Answer Key 2024 | To be notified |
CSIR NET Result | To Be Notified |
The CSIR NET 2024 test will most likely be administered in two sessions. See the entire schedule below:
CSIR NET Exam Day Events | CSIR NET 2024 First Shift Timings | CSIR NET 2024 Second Shift Timings |
---|---|---|
Timing of exam | 9:00 AM-12:00 PM | 3:00 PM-6:00 PM |
Duration of exam | 3 hours without a break | 3 hours without break |
Entry into the exam centre | 7:00-8:00 AM | 1:00-2:00 PM |
Entry into the exam hall/room | 8:15-8:30 AM | 2:15-2:30 PM |
Checking of admit cards by the invigilator | 8:30-8:45 AM | 2:30-2:45 PM |
Sitting on the seat in the exam hall | 8:45 AM | 2:45 PM |
Instructions by the invigilators | 8:45-8:55 AM | 2:45-2:55 PM |
Test commences | 9:00 AM | 3:00 PM |
Test concludes | 12:00 PM | 6:00 PM |
The NTA releases the CSIR NET admission card a few days before the exam. Candidates may get their CSIR NET 2024 admit card by entering their registered accounts on the exam’s official website.
Candidates who wish to register for the CSIR-UGC NET 2024 examination must check the eligibility criteria. The NTA (National Testing Agency) determines the qualifying conditions based on age, educational qualifications, and country.
Candidates must have either of the following credentials with at least 55% (for General and OBC) or 50% (for Scheduled Caste (SC)/Scheduled Tribe (ST)/Persons with Disability (PwD) candidates).
The table below details the CSIR NET 2024 Educational Qualification by subject:
Subject | Qualification Required |
Chemical Science | Candidates must have an MSc/BS/B-Tech degree in Chemistry or an equivalent qualification. |
Earth, Ocean, Atmospheric and Planetary Science | Candidates must have an MSc/BS-MS/BS-4 Years/B-Pharma or an equivalent degree in Earth, Ocean, Atmospheric, and Planetary Science. |
Life Science | Candidates with academic qualifications in Life Sciences are required. |
Mathematics | Candidates must have an MSc/BS-MS/BS/B-Tech degree in Mathematics or an equivalent qualification. |
Physical Science | Candidates must have an MSc in Physics or a BS-MS in Physics, or an equivalent certificate. |
As of July 1, 2023, the maximum age restriction for the granting of a Joint Research Fellowship (JRF) is 28 years.
Category | Age Limit |
SC/ ST/ PwD/ Female | 33- years |
OBC (non-creamy layer) | 31- years |
Candidates may also examine the age-related relaxation for candidates from the restricted categories.
Category | Age Limit Relaxation Years |
Female | 5 |
Scheduled Caste | 5 |
Scheduled Tribe | 5 |
OBC (non-creamy layer) | 3 |
Persons with disability (PwD) | 5 |
Note: Some important points to remember
The CSIR has established criteria for reducing the minimum marks necessary and the maximum age limit for candidates from various reserved categories (SC/ST/OBC-NCL/PwD) and female applicants.
In terms of categories CSIR NET, the following table details the relaxation of marks for qualified applicants from reserved categories:
Category | Marks Relaxation Percentage |
Other Backward Classes | 5% |
Scheduled Caste | 5% |
Scheduled Tribe | 5% |
Candidates must indicate whether they are applying for JRF or LS positions based on their eligibility and indicate their preference in this manner on the CSIR UGC NET application form.
The NTA will release the CSIR NET 2024 Notification and the CSIR NET Application Form 2024 on the official website csirnet.nta.nic.in.
Candidates are advised to be careful to finish their payment since no application will be approved without payment of the required fee.
The entire CSIR Net 2024 Application Fee per category is shown below. No application will be deemed submitted without payment of the fee. The CSIR NET application cost must be paid online by debit card, credit card, or internet banking by applicants. The application fee is broken down per type as follows.
Category | Application Fee (Rs.) |
General | 1100 |
OBC (Non-creamy layer) | 550 |
SC/ST/Third Gender | 275 |
PwD | Nil |
Candidates can complete the CSIR NET online form 2024 by following the instructions below:
Candidates must follow the actions listed below to register online:
Personal Details | |
Name | Date Of Birth |
Parents Name | ID Type |
Gender | ID Card Number |
Contact Details | |
Permanent Address | Mobile Number |
Email ID |
Candidates must click the “Complete Application Form” option to continue filling out the CSIR UGC NET online application form. The information that applicants must include in the form is listed below.
Candidates must next upload scanned copies of their signature and photo according to the guidelines.
Documents | Uploading Format | Size (in KB) |
Signature | JPG | 4KB – 30KB |
Photograph | JPG | 10KB – 200KB |
Upon successful payment of the charge, a confirmation page will be created. The confirmation page must be printed at least three times by candidates, and they must save all copies for their records.
The CSIR- UGC NET 2024 application form must be completed with the following details and supporting documentation:
A few days before the test, the CSIR UGC NET admit card will be made accessible. The admission card will provide further information about the schedules, exam location, and other factors.
Candidates who plan to sit for the exam must bring the CSIR NET Admit Card and an original picture ID evidence to the exam site. The CSIR NET 2024 admit card must be brought to the designated test location. Candidates who do not have their admission card when it is needed might not be allowed to attend the exam paper.
NTA does not distribute hall tickets through mail, courier, or email. It will be accessible online at the CSIR’s main website.
Applicants to download their CSIR UGC NET test admission cards may use the procedures listed below:
Details Available on CSIR- UGC NET Exam Admit Card
The admission card includes the following information regarding the applicant and test.
Items Permitted at the Exam Centre 2024
Candidates to the CSIR NET testing sites may bring the following objects:
The NET syllabus is public by the CSIR on their official website. Candidates who plan to take the exam can download the PDF for the course materials for each of the five subjects and use them offline. The CSIR NET exam consists of three parts, A, B, and C. The Part A syllabus is the same for everyone, while the Part B and C syllabuses depend entirely on the candidates’ chosen subjects. Candidates can choose the subject when completing their online application.
The CSIR NET Syllabus is a collection of topics from various subjects for which the exam is given. All applicants must be familiar with the exam topics to improve their chances of selection. Part-A is based on General Science, Quantitative Reasoning and analysis, and Research Aptitude. Part B is based on the concerned subject and Part- C is based on the scientific concepts or their applications.
Subjects | Codes |
Chemical Science | 701 |
Earth, Atmospheric, Ocean, and Planetary Science | 702 |
Life Science | 703 |
Mathematical Science | 704 |
Physical Science | 705 |
Chemical Sciences | Earth, Atmospheric, Ocean & Planetary Sciences | Life Sciences | Mathematical Sciences | Physical Sciences |
Branches of Chemistry | Oceans and Atmosphere | Cellular Organization | Analysis | Mathematical Methods of Physics |
Organic Chemistry | Environmental Earth Sciences | Inheritance Biology | Algebra | Atomic & Molecular Physics |
Inorganic Chemistry | Mineralogy and Petrology | Developmental Biology | Classical Mechanics | Electromagnetic Theory |
Medicinal Chemistry | The Earth and the Solar System | Molecules and their Interaction Relevant to Biology | Linear Integral Equations | Thermodynamic and Statistical Physics |
Physical Chemistry | Earth Materials, Surface Features and Processes | Applied Biology | Calculus of Variations | Nuclear and Particle Physics |
Catalysis and Green Chemistry | Geophysics | Diversity | Partial Differential Equations (PDEs) | Condensed Matter Physics |
Chemistry in Nanoscience and Technology | Palaeontology and its applications | Fundamental Processes | Numerical Analysis | Quantum Mechanics |
Supramolecular Chemistry | Marine Geology and Palaeontology | Evolution and Behaviour | Ordinary Differential Equations (ODEs) | Electronics and Experimental Methods |
Exam questions for the CSIR UGC NET 2024 will be objective-type multiple-choice and asked from the applicants’ selected topic. View a summary of the test pattern in the table below.
Particulars | Exam Pattern |
Exam Mode | Online – Computer Based Test (CBT) |
Exam Duration | 3 Hours (180 minutes) |
Total Sections | 3 in each paper |
Total Questions | Total Questions- 610 Need to Attempt- 310 |
Types of Questions | MCQ: 4 options with 1 correct answer |
Total Marks | 200 for each paper (Paper1 and Paper 2) |
Negative Marking | Yes |
Language | English and Hindi |
The test would be divided into three sections for each subject, which are covered in depth in the following sections:
CSIR- UGC NET Marking Schemes (Subject-wise) | ||||
Subjects | No. of Questions | To be attempted | Marking Scheme | Negative Marking |
Chemical Sciences | 120 Part A- 20 Part B- 40 Part C- 60 | 75 Part A- 15 Part B- 35 Part C- 25 | 200 Part A- 2 Part B- 2 Part C- 4 | Part A- 0.5 Part B- 0.5 Part C- 1 |
Earth, Atmospheric, Ocean, and Planetary Sciences | 150 Part A- 20 Part B- 50 Part C- 80 | 75 Part A- 15 Part B- 35 Part C- 25 | 200 Part A- 2 Part B- 2 Part C- 4 | Part A- 0.5 Part B- 0.5 Part C- 1.32 |
Life Sciences | 145 Part A- 20 Part B- 50 Part C- 75 | 45 Part A- 15 Part B- 35 Part C- 25 | 200 Part A- 2 Part B- 2 Part C- 4 | Part A- 0.5 Part B- 0.5 Part C- 1 |
Mathematical Sciences | 120 Part A- 20 Part B- 40 Part C- 60 | 60 Part A- 15 Part B- 25 Part C- 20 | 200 Part A- 2 Part B- 3 Part C- 4.75 | Part A- 0.5 Part B- 0.75 Part C- 0 |
Physical Sciences | 75 Part A- 20 Part B- 25 Part C- 30 | 55 Part A- 15 Part B- 20 Part C- 20 | 200 Part A- 2 Part B- 3.5 Part C- 5 | Part A- 0.5 Part B- 0.875 Part C- 1.25 |
Candidates can review the subject-specific CSIR NET Best Books 2024 in the table below to assist them prepare for the exam.
Subjects | Book Name | Author/Publisher |
Chemical Sciences | UGC-CSIR JRF/ NET Chemical Sciences (Chemistry) | Trueman’s |
Earth Sciences | Joint CSIR-UGC NET Earth, Atmospheric, Ocean, and Planetary Sciences | R Gupta’s |
Life Sciences | UGC CSIR NET/ SET (JRF & LS) Life Sciences | Arihant |
Mathematical Sciences | CSIR-UGC NET/ SET (JRF & LS) Mathematical Sciences | Khanna Publishers |
Physical Science | CSIR-UGC NET/ JRF/ SET Physical Sciences | Upkar’s |
On January 06, 2024, that year’s CSIR UGC NET tentative answer key was made available online at https://csirnet.nta.nic.in. The National Testing Agency (NTA) conducts the CSIR UGC NET(commonly known as CSIR NET) exam at the national level to select applicants for the award of Junior Research Fellowships (JRF).
All candidates on the official website using the login information created during the registration process may see the CSIR NET Exam Answer Key. Candidates can use the procedures listed below to verify the CSIR NET answer key:
Candidates can contest the CSIR NET Exam Answer Key 2024 by doing the following actions:
After the CSIR NET 2024 test has been successfully administered, the National Testing Agency (NTA) will publish the results on its official website. Candidates may see their results by visiting the official website when the CSIR NET Results are released online. The candidates who passed the test will receive their eligibility certificates and JRF Award Letters from NTA following the announcement of the CSIR NET Result 2024. The job of Assistant Professor at Indian colleges and universities is also open to qualified people.
Candidates can use the methods listed below to verify their CSIR UGC NET 2024 result:
Step 1: Go to CSIR NET’s official website.
Step 2: Select “Joint CSIR UGC NET June 2024 Score Card” from the list of links.
Step 3: Provide the following information.
Step 4: Select “Submit.”
Step 5: View and save the CSIR NET scorecard and results.
If applicants forget their application number, they can obtain a new one on the exam’s official website by following the instructions below:
Step 1: Explore the CSIR NET website.
Step 2: Select the link for the result.
Step 3: Select the ‘Forgot Application No.’ link.
Step 4: Type in the information below:
Step 5: Press the button labelled “Get Application Number.”
In due order, NTA issues eligibility certificates and JRF award letters to candidates who complete the CSIR NET exam. Then, all qualified individuals can apply for an assistant professorship at an Indian university or college or do research in the field of science of their choice.
On the official website, certificate.nta.ac.in, the NTA has made the CSIR UGC NET 2024 certifications available. Candidates may now use the below-listed procedure to get their CSIR NET certificate for 2024.
Candidates interested in a teaching and research career should take the CSIR NET test. After passing this admission exam, the chosen individual can pursue a PhD at a reputable university. If you pass the NET JRF exam, you are qualified for the numerous occupations listed in the table below.
Job Position | Monthly Expected Salary (in INR) |
Junior Research Fellows | 31,000 +HRA (Depends on the Institution) |
Senior Research Fellows | 35,000+HRA (Depends on the Institution) |
Assistant Professor | 45,000 |
Associate Professor | 80,000 |
Professor | 82,000 |
For the first two years, a JRF selected through CSIR-NET will receive a monthly stipend of Rs.31000. A yearly contingent grant of Rs.20000 will also be given to the university or institution for each fellow. The terms and conditions of the CSIR, UGC, or Research Scheme, as appropriate, will govern the Fellowship. The Fellowship will be upgraded to SRF (NET) after two years as JRF.
If the Fellow is enrolled in a PhD, the stipend will be increased to Rs. 35,000/- per month for the third and subsequent years, based on an assessment of the Fellow’s research progress/achievements through an interview by an Expert Committee consisting of the Guide, Head of the Department, and External Member from outside the University/Institute who is an expert in the relevant field.
The CSIR NET Cut-Off is the score at which candidates will be chosen for JRF and Lectureship positions. To pass the CSIR NET exam, candidates must score at least 33% in the General, EWS, and OBC categories and 25% in the SC, ST, and PwD categories. There are three parts to the CSIR UGC NET: Parts A, B, and C. However, there are no sectional cut-offs; instead, the cut-off is determined by adding the marks obtained in each component. The cut-off marks vary for both the categories, Junior Research Fellowship (JRF) and Lectureship.
CSIR NET JRF Cut-off (Expected) | ||||||
Subject | UR (%) | EWS (%) | OBC (%) | SC (%) | ST (%) | PWD (%) |
Chemical Science | 52.75 | 46.25 | 45.5 | 36.25 | 27.25 | 25 |
Earth Science | 60.86 | 54.79 | 53.06 | 46.4 | 42.81 | 26.4 |
Life Science | 98.78 | 96.06 | 96.22 | 90.53 | 84.87 | 64.76 |
Mathematical Science | 49.25 | 44.87 | 42.75 | 34.37 | 27 | 25 |
Physical Science | 38.81 | 33 | 33 | 25 | 25 | 25 |
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Candidates can retrieve their UGC NET application number or password for CSIR NET online if they have forgotten it. To retrieve your Application Number/Roll Number or Password, follow the steps listed below:
1.) Visit the official website.
2.) Select the button for the application form.
3.) Select the link labeled “Forgot Application Number.”
4.) Enter your name, father’s name, mother’s name and date of birth.
5.) Enter the security pin shown on the screen.
6.) The “Get Application Number” button should be clicked.
The National Eligibility Test (NET), administered on behalf of the University Grants Commission (UGC), determines whether Indian citizens are eligible for assistant professor positions in Indian universities and colleges. NTA administers CSIR NET to select candidates for the JRF award and eligibility for assistant professor positions in science-only fields. NTA administers UGC NET to choose candidates for JRF awards and eligibility for assistant professor positions in all other subjects (total of 81).
The CSIR NET exam is considered to be highly competitive and tough. While studying for the exam, you gain much knowledge and experience, so passing it is not just like having a degree. With others, you can impart your wisdom and experience. Candidates who pass the CSIR NET examination can apply for junior research fellowships and teaching positions. The NET exam is held twice a year, in June and December, by NTA on behalf of UGC. To sit for this exam, candidates must have earned a minimum of 55% on their Master’s degree. Candidates who pass the UGC NET exam are eligible for lecturer positions at IITs and NITs as well as research programs (JRF)
The overall NTA score represents the proportion of candidates who, in that session, scored EQUAL TO OR BELOW (same or lower raw scores) that specific candidate. It says nothing about your qualifications or lack thereof. Most likely, the cut-off will be the same as last year. But it should be increased by five marks (Not a percentage). According to the CSIR NET answer key, marks will be awarded for accurate responses. This raw score will create the “NTA score” or percentile. All candidates’ scores will be combined to create the final merit list.
Four to five months after the results are announced, UGC and CSIR upload the certificate. Candidates who qualify for lectureships and research positions as JRFS in Indian universities are given this certificate. To download CSIR certificates, follow these simple steps:
1: Sign in to the CSIR website.
2: Enter the required details as mentioned on the website and press the “submit” button.
3: Download the CSIR certificate visible on the screen.
4: Print the hard copy later for your records.
Download Certificate (Part II and III)
1: Access the UGC website.
2: Press the button to download the CSIR-UGC Test e-certificate.
3: There will then be a “Yes” or “No” option for you to select.
4: Click “Yes” if you already have your password via OTP.
5: If you haven’t received the password via OTP, choose No.
6: Complete all the necessary information and download the certificate.
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